Difference+of+Squares

these are the steps for solving a difference in squares equation :

 * == For //a//2 – c2, do the parentheses  ==


 * == ...put the first squared number the front: ==

(//a// )(//a// )

 * == ...put the second squared number in back: ==

(//a// c)(//a// c)

 * == ...and alternate the signs in the middles: ==

//x//2 – 16 = //x//2 – 42 = **(//x// – 4)(//x// + 4)**

 * ** Factor   4//x//2 – 25  **

4//x//2 – 25 = (2//x//)2 – 52 = ** (2//x// – 5)(2//x// + 5   )  **

 * ==** Factor   9//x//6 – //y//8  **==

9//x//6 – //y//8 = (3//x//3)2 – (//y//4)2 = **(3//x//3 – //y//4)(3//x//3 + //y//4)**

 * ==** Factor   //x//4 – 1  **  Copyright © Elizabeth Stapel 2000-2011 All Rights Reserved  ==

//x//4 – 1 = (//x//2)2 – 12 = (//x//2 – 1)(//x//2 + 1)
== Note that I'm not done yet, because   //x//2 – 1   is itself a difference of squares, so I need to apply the formula again to get the fully-factored form. Since  //x//2 – 1 = (   //x// – 1)(//x// + 1)  , then:  ==

The answer to this last exercise depended on the fact that 1 , to any power at all, is still just   1.
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